Controls
View
Template sequence
Step through the enzymes
Pick an enzyme from the list, or click its icon, to see its job on its own
Readings
- Bases copied
- 0
- Okazaki fragments made
- 0
- Chargaff (A=T, G≡C)
- A=T 25% · G≡C 25%
- Hydrogen bonds
- 30
- Hybrid / light fraction
- 25% / 75%
- Template length
- 12
How to use this simulation
- Start on the "Replication fork" view: the parent DNA is still joined on the right, helicase is unwinding it right at the fork, and two new strands are growing on the left.
- Work through the "Step through the enzymes" list one at a time: watch where helicase acts, when primase lays a primer, how polymerase extends a strand, and when ligase flashes to seal a join.
- Switch the "Template sequence" between the three samples and watch the base-pair colours change; then pick "Type your own" and type A, T, G, C letters of your own to see the complementary strand computed live.
- Move to "Zoom on base pairing" and count the dashed lines between each pair — two for A–T, three for G–C.
- Open "Meselson-Stahl experiment" and drag the Generation slider up from 0: watch the heavy, hybrid and light bands in the tube change, with the exact percentages printed on the right.
- Watch the readings panel: bases copied and Okazaki fragments made keep climbing while it plays — press Reset any time to start those two counters back at zero.
How a cut heals: DNA gets copied every single day
A small cut on your hand closes up in a few days. Hair keeps growing after a cut. Blood cells you lose get replaced. Behind every one of these is the same event: old cells die and new cells are built, and each new cell needs a DNA copy that matches the original letter for letter. Get even one letter wrong in the wrong place and a cell can misbehave — sometimes badly enough to cause disease.
So how does a long DNA molecule inside a cell make an accurate copy of itself? That question is exactly what DNA replication answers. This page walks through DNA's structure, how it is unwound and copied, which enzyme does which job, and how two scientists proved the copying method is "semi-conservative" using nothing more than heavy and light nitrogen and a centrifuge.
The same copying principle, run in a test tube instead of a cell, is what lets forensic scientists identify a suspect from a single hair or a trace of saliva: a technique called PCR turns a few DNA molecules into billions of copies. The real-life section near the end of this page covers it in more detail.
Starting from zero: what DNA replication actually is
DNA (deoxyribonucleic acid) is a twisted ladder — a double helix — made of two strands wound around each other. Each strand is a chain of nucleotides, and every nucleotide has three parts: a deoxyribose sugar, a phosphate group, and one of four nitrogen bases. The sugars and phosphates link up to form the sugar-phosphate backbone, while the bases point inward, like the rungs of the ladder.
The four bases are adenine (A), thymine (T), guanine (G) and cytosine (C). A on one strand always pairs with T on the other, and G always pairs with C. This is the Watson–Crick base-pairing rule, from the double-helix structure James Watson and Francis Crick proposed in 1953 (built on Rosalind Franklin's X-ray images). The two strands run in opposite directions — one goes 5′ to 3′ while the other goes 3′ to 5′ right beside it — an arrangement called antiparallel.
Write the definition like this: DNA replication is the biochemical process in which the two strands of a DNA molecule separate, and each old strand is used as a template to build a new, complementary strand, producing two identical double-stranded DNA molecules. Each new molecule keeps one original strand and gains one brand-new strand — that half-and-half split is exactly what "semi-conservative" means.
Replication happens during the S phase of the cell cycle, right before a cell divides. The spot where the two strands first separate is called the origin of replication; a bacterium's single circular chromosome has one origin, and two replication forks race outward from it in opposite directions.
Key terms for this topic
These words come up in almost every question on this topic — learn them once and the rest reads easily.
| Term | Plain-English meaning |
|---|---|
| Nucleotide | DNA's building block: a sugar + a phosphate + one base (A/T/G/C) |
| Sugar-phosphate backbone | The chain that holds a strand's shape together; bases hang off it |
| Antiparallel | The two strands run in opposite directions: one 5′→3′, the other 3′→5′ |
| Replication fork | The Y-shaped point where the double helix splits into two single strands |
| Helicase | The enzyme that breaks the hydrogen bonds holding the two strands together |
| SSB proteins | Single-strand binding proteins; keep an unwound strand from snapping back together |
| Primase | The enzyme that lays down a short RNA primer, giving polymerase a starting point |
| DNA polymerase | The enzyme that extends a new strand 5′→3′, adding the correct complementary base each time |
| Leading strand | The new strand made continuously, in the same direction the fork is moving |
| Lagging strand | The new strand made in short pieces, in the direction opposite the fork |
| Okazaki fragment | Each short piece of DNA made on the lagging strand, named after Reiji and Tsuneko Okazaki (1968) |
| Ligase | The enzyme that seals the gap between two DNA fragments into one continuous strand |
| Semi-conservative | The rule that every new DNA molecule keeps one old strand and gains one new one |
| Proofreading | Polymerase's own ability to catch and remove a wrongly added base |
Base pairing, hydrogen bonds and Chargaff's rule
In the 1950s, biochemist Erwin Chargaff measured the base composition of DNA from many different species and found something striking: in every sample, the amount of adenine equalled the amount of thymine, and the amount of guanine equalled the amount of cytosine — even though the overall A+T to G+C ratio varied a lot between species. This pattern, now called Chargaff's rule, became one of the clues Watson and Crick used to work out base pairing.
The reason sits in the number of hydrogen bonds. A and T form two hydrogen bonds; G and C form three. That extra bond makes a G–C pair a little more stable and more heat-resistant than an A–T pair. The "Zoom on base pairing" view in the simulation draws exactly these dashed hydrogen-bond lines.
The table below shows the simulation's three sample sequences. The first is perfectly balanced (25% of each base), the second is GC-rich and the third is AT-rich. Notice that %A = %T and %G = %C in every single one — that is Chargaff's rule holding regardless of the actual sequence. The GC-rich sample also carries more hydrogen bonds overall, so that stretch of DNA is more heat-stable.
A = T, G = CChargaff's rule, within one DNA molecule
(A + G) = (T + C)purines always equal pyrimidines in count
| Sample sequence (5′→3′) | %A | %T | %G | %C | Hydrogen bonds |
|---|---|---|---|---|---|
| ATGCGTACGCAT | 25% | 25% | 25% | 25% | 30 |
| GGGGCCCCATAT | 17% | 17% | 33% | 33% | 32 |
| ATATATGCATAT | 42% | 42% | 8% | 8% | 26 |
The semi-conservative model and the Meselson–Stahl experiment
Once the double-helix structure was known, three models were proposed for how replication might actually copy it. Semi-conservative: each new molecule keeps one old strand and gains one new strand. Conservative: the two original strands would stay together, and a completely separate, all-new molecule would form. Dispersive: old and new segments would end up mixed together in both resulting molecules.
In 1958, Matthew Meselson and Franklin Stahl designed an elegant experiment to tell the three apart. They grew E. coli bacteria for many generations in a medium containing the heavy nitrogen isotope ¹⁵N, so both strands of every bacterium's DNA became heavy. They then switched the bacteria to an ordinary, light ¹⁴N medium and, after each generation, extracted the DNA and spun it in a caesium chloride (CsCl) density-gradient ultracentrifuge. In this setup heavy DNA settles lower in the tube, light DNA settles higher, and hybrid DNA (one heavy strand plus one light strand) bands exactly in between.
After exactly one generation, every molecule of DNA formed a single band at the intermediate (hybrid) position — no pure heavy band remained. That single result already rules out the conservative model, which would have kept a pure heavy band and produced a pure light band alongside it from generation one. After a second generation, half the DNA was hybrid and half was fully light, appearing as two sharp bands rather than one gradually shifting band — which is what a dispersive model would have produced instead. The results matched the semi-conservative model, and only that model.
The hybrid fraction at any generation follows a simple rule: after n rounds of replication, the fraction of duplexes that are hybrid equals (½)^(n−1), and the rest are fully light. At generation 3, for example, 25.00% of the DNA is hybrid and 75.00% is fully light; by generation 5 the hybrid fraction has fallen to just 6.25%, with 93.75% fully light. No generation from n = 1 onward keeps a fully heavy duplex, because every original heavy duplex splits into two separate daughter molecules the very first time it replicates. The table below runs the numbers from generation 0 through 6.
hybrid fraction = (1/2)^(n − 1), n ≥ 1under semi-conservative replication, at generation n
| Generation (n) | Heavy band (¹⁵N-¹⁵N) | Hybrid band (¹⁵N-¹⁴N) | Light band (¹⁴N-¹⁴N) |
|---|---|---|---|
| 0 | 100.00% | 0.00% | 0.00% |
| 1 | 0.00% | 100.00% | 0.00% |
| 2 | 0.00% | 50.00% | 50.00% |
| 3 | 0.00% | 25.00% | 75.00% |
| 4 | 0.00% | 12.50% | 87.50% |
| 5 | 0.00% | 6.25% | 93.75% |
| 6 | 0.00% | 3.13% | 96.88% |
The replication enzymes and their jobs
No single enzyme carries out replication alone — it is teamwork, and each member has one specific job. The "Step through the enzymes" list in the simulation lets you pick each one and watch it act on its own; the table below summarises what each does.
Two more helper enzymes are worth knowing beyond these five. Topoisomerase (gyrase in bacteria) relieves the extra twisting (supercoiling) that builds up just ahead of the fork, which would otherwise stop helicase from unwinding any further. And in prokaryotes, DNA polymerase I removes each RNA primer and fills the gap with DNA before ligase makes the final seal.
| Enzyme | Job |
|---|---|
| Helicase | Breaks the hydrogen bonds between the two strands, unwinding the DNA and creating the replication fork |
| SSB proteins | Hold the separated single strands apart so they cannot re-anneal |
| Topoisomerase | Cuts and releases the extra supercoiling that builds up ahead of the fork |
| Primase | Lays down a short RNA primer; DNA polymerase can only extend an existing strand, never start one from nothing |
| DNA polymerase | Adds the correct complementary nucleotide after the primer, always 5′→3′, and proofreads its own mistakes |
| Ligase | Seals the phosphodiester gaps between Okazaki fragments, turning the lagging strand into one continuous strand |
Leading strand, lagging strand and Okazaki fragments
DNA polymerase has one strict rule: it can only extend a new strand 5′→3′, never the other way. But the two old template strands run in opposite directions (antiparallel), so at the very same fork, the two new strands have to be built by two different strategies.
The leading strand: continuous, uninterrupted
On the template strand whose 3′ end faces the fork, a new strand can be extended 5′→3′ in exactly the same direction the fork is moving. That needs only one primer, laid down once at the very start, after which polymerase keeps pace with the fork continuously. This new strand is the leading strand.
- Primers needed: just one, at the start
- Made: continuously, toward the fork
- Enzyme: DNA polymerase III in E. coli, working non-stop once it starts
The lagging strand: piece by piece, Okazaki fragments
On the other template strand, whose 5′ end faces the fork, a new strand can only be built by moving away from the fork. As the fork exposes more template, primase repeatedly lays a fresh short RNA primer, and polymerase extends a short piece from it until it reaches the previous piece.
Each of these short pieces is called an Okazaki fragment, first identified in 1968 by Japanese scientists Reiji Okazaki and his wife Tsuneko Okazaki. Once a fragment is finished, ligase joins it to the one before it — after the RNA part of each primer is removed and replaced with DNA (DNA polymerase I's job in bacteria).
This simulation simplifies both figures for clarity: each Okazaki fragment is drawn as exactly 6 bases long with a 2-base primer. In real cells a eukaryotic fragment averages roughly 200 nucleotides (bacterial fragments run longer, 1,000-2,000 nucleotides), and the real timing is far less tidy than the animation shows.
- Primers needed: repeatedly, one per fragment
- Made: in pieces, away from the fork
- Ligase seals each fragment to the last, making one continuous strand
Proofreading and mutation
DNA polymerase is remarkably accurate, but not perfect. Its raw error rate — a wrong base slipping in — is roughly 1 mistake in every 100,000 bases. But polymerase carries its own 3′→5′ exonuclease activity, which recognises a mismatched base right after it's added, removes it, and replaces it correctly. This proofreading step brings the error rate down to about 1 in 10,000,000.
After replication, a separate mismatch repair system catches almost all of what proofreading missed. Combined, the final error rate falls to roughly 1 mistake in every 1,000,000,000 bases copied. Whatever tiny fraction slips past both proofreading and repair can remain as a permanent change to the DNA sequence — a mutation.
Mutations are not automatically bad. Most are neutral, some are harmful (disabling a working gene, for instance), and some are even beneficial, supplying the raw material evolution works with. But when the proofreading or repair machinery itself breaks down, the mutation rate climbs sharply — one of the routes to cancer.
DNA vs RNA: the differences that matter here
DNA and RNA are both nucleic acids, but they differ in structure and job in ways this topic keeps returning to.
| Feature | DNA | RNA |
|---|---|---|
| Sugar | Deoxyribose | Ribose |
| Bases | A, T, G, C | A, U (uracil instead of thymine), G, C |
| Strands | Usually double-stranded | Usually single-stranded |
| Stability | More stable, suited to long-term storage | Less stable |
| Main role | Stores and passes on genetic information | Carries messages (mRNA), builds proteins (rRNA, tRNA), or primes replication |
| Role in this topic | What gets copied | The temporary primer primase lays down |
Try these experiments in the simulation
Press Reset before each experiment if you want the bases-copied and Okazaki-fragment counters to start back at zero.
Experiment 1: isolate each enzyme in turn
On the "Replication fork" view, pick helicase, SSB, primase, polymerase and ligase one at a time from the enzyme list. Each choice draws a glowing ring around that enzyme's icon, so it is easy to see exactly where it acts.
Experiment 2: compare the leading and lagging strand pace
Notice that the leading strand (the top arm) grows at exactly the same pace as the fork, always. The lagging strand (the bottom arm), instead, grows one Okazaki fragment at a time, each one starting fresh, until ligase flashes and joins it to the fragment before it.
Experiment 3: type your own template
Under "Template sequence", choose "Type your own" and type any combination of A, T, G, C letters into the box. Switch to "Zoom on base pairing" and watch the complementary strand recompute underneath your sequence instantly, with the readings panel updating Chargaff's percentages and the hydrogen-bond count to match.
Experiment 4: raise the generation in Meselson–Stahl
Open "Meselson-Stahl experiment" and slide Generation up slowly from 0. At generation 1 the tube shows one hybrid band and nothing else; from there the light band keeps growing and the hybrid band keeps shrinking, but never quite reaches zero.
Experiment 5: compare a GC-rich and an AT-rich sample
Switch between sample 2 (GC-rich) and sample 3 (AT-rich) and compare the "Hydrogen bonds" reading. Even at the same length, the GC-rich sequence carries more total hydrogen bonds.
Solved problems
Every number below is computed straight from the simulation's own model, so it can never drift from what the animation shows.
Problem 1: find the complementary strand (and keep it antiparallel)
The simulation's first sample template (5′→3′) is: ATGCGTACGCAT. Applying Watson–Crick pairing base by base gives the complementary strand: TACGCATGCGTA. That new strand runs in the opposite direction to the template, so while it pairs up exactly as written, its own 5′ end sits at the position labelled 3′ on the template's side — the two strands are antiparallel, not simply reversed copies of each other.
Over these 12 base pairs, A appears 3 times (so T also appears 3 times on the complementary strand at those positions), and G appears 3 times (so does C) — template and complement always carry matching counts, which is exactly why Chargaff's rule holds.
Problem 2: if %G = 20%, find the percentage of every other base
By Chargaff's rule, %G = %C, so %C is also 20%. That leaves 100 − 20 − 20 = 60% to be split evenly between A and T. So %A = %T = 30%. Check it: 30% + 30% + 20% + 20% = 100%.
%A = %T = (100 − 2 × %G) ÷ 2Chargaff's rule, run in reverse
Problem 3: count the hydrogen bonds in this template
Sample 1 contains 3 A's, 3 T's, 3 G's and 3 C's. Each A–T pair carries 2 hydrogen bonds and each G–C pair carries 3. Since every A pairs with a T and every G pairs with a C, the total is (3 × 2) + (3 × 3) = 30 hydrogen bonds.
total H-bonds = (count of A × 2) + (count of G × 3)
Problem 4: how many Okazaki fragments does a 6,000-nucleotide stretch need
A eukaryotic Okazaki fragment averages about 200 nucleotides. So copying a 6,000-nucleotide lagging-strand template needs 6,000 ÷ 200 = 30 fragments — each needing its own RNA primer at the start and its own ligase seal at the end.
Problem 5: the fraction of heavy DNA at generation 3 and 5
At generation 3, the hybrid-duplex fraction is (½)^(3−1) = 25.00%, leaving 75.00% fully light and 0% fully heavy. At generation 5, hybrid has fallen to 6.25% and light has risen to 93.75%. Measured per individual strand rather than per duplex, the fraction of surviving original heavy strands at generation 3 is instead (½)^3 = 12.50% — a different number, because each duplex contains two strands.
Problem 6: how long is E. coli's entire chromosome, stretched out
E. coli's circular chromosome holds roughly 4,600,000 base pairs. At 0.34 nm per base pair, stretched straight it measures 4,600,000 × 0.34 nm = 1,564 µm = 1.56 mm. The E. coli cell itself is only about 2 µm long, so this one molecule is roughly 782 times longer than the cell that packs it in — which it manages only by supercoiling tightly. With 10 base pairs per turn of the helix, the whole chromosome makes about 460,000 full turns.
length = number of base pairs × 0.34 nm/bp
Problem 7: how long replicating the whole chromosome actually takes
A real E. coli replication fork adds roughly 1,000 nucleotides per second, and 2 forks run outward from the one origin at the same time. So the time needed is 4,600,000 ÷ 2 ÷ 1,000 = 2,300 seconds, or about 38.3 minutes. This simulation shows 4 bases per second purely so the process is watchable — it is not the real speed.
Real-life uses of DNA replication
PCR (the polymerase chain reaction) copies the exact logic of DNA replication inside a lab tube, turning a tiny amount of DNA into billions of copies. Kary Mullis invented it in 1983 and won a Nobel Prize for it. It relies on a heat-tolerant DNA polymerase (Taq polymerase, first isolated from bacteria living in hot springs), primers, and repeated heating-and-cooling cycles that double the amount of DNA every cycle.
DNA fingerprinting (DNA profiling) uses PCR to amplify a trace sample — a hair, a drop of blood, a swab of saliva — enough to examine a handful of short, repeated regions called STRs. The length pattern of those regions is unique to almost everyone except identical twins, which is why DNA profiling is central to forensic identification and paternity testing today.
Whole-genome sequencing, gene therapy, crop and livestock breeding, disease-diagnosis kits, and the RT-PCR test used throughout the COVID-19 pandemic all rest on the same underlying ability: copying DNA (or converting RNA into DNA first) accurately, at scale.
Common mistakes to avoid
Run through this list before you write an exam answer.
- Writing "replication is conservative" — wrong. The Meselson–Stahl experiment (1958) proved it is semi-conservative.
- Assuming DNA polymerase can start a brand-new strand from nothing — wrong. It can only extend an existing primer or strand, which is exactly why primase has to act first.
- Assuming the leading and lagging strands are made by different enzymes — wrong. The same DNA polymerase builds both; only the direction and the number of primers differ.
- Thinking Okazaki fragments only occur in bacteria — wrong. Both eukaryotes and prokaryotes build the lagging strand in Okazaki fragments; only the typical fragment length differs.
- Saying a light band appears at generation 1 in Meselson–Stahl — wrong. Generation 1 is entirely hybrid; a light band only appears from generation 2 onward.
- Mixing up which pair has more hydrogen bonds — remember G–C has three, A–T has two, which is also why GC-rich DNA is more heat-stable.
Exam corner
DNA replication is a staple topic across school and college biology syllabi worldwide. Expect questions on matching each enzyme to its job, applying Chargaff's rule to a given percentage, interpreting the Meselson–Stahl bands, and defining an Okazaki fragment — all of which this page covers with computed, checkable numbers rather than memorised facts.
A sample extended-response question
Scenario: a short DNA strand reads ATGCGTACGCAT (5′→3′). Meselson and Stahl ran a heavy-to-light nitrogen switch experiment in E. coli, and by the second generation observed two bands of equal intensity.
- a. Define a replication fork.
- b. Write the complementary strand for the sequence above and calculate how many hydrogen bonds it contains.
- c. Explain why the second generation produces two bands of equal intensity rather than one.
- d. Analyse how this result supports the semi-conservative model and rules out the conservative model.
Quick facts for multiple-choice questions
Memorise these and a handful of marks become close to automatic.
- Double-helix structure proposed by: Watson and Crick (1953)
- Semi-conservative replication proved by: Meselson and Stahl (1958), in E. coli
- Okazaki fragments discovered by: Reiji and Tsuneko Okazaki (1968)
- Unwinds DNA: helicase; seals nicks: ligase
- A–T bonds: 2; G–C bonds: 3
- New strands always grow: 5′→3′
- PCR invented by: Kary Mullis (1983)
One-screen revision summary
Read this the night before the exam.
- Definition: one DNA molecule makes two identical copies, each with one old strand and one new strand (semi-conservative).
- Chargaff's rule: %A = %T, %G = %C. A–T has 2 hydrogen bonds, G–C has 3.
- Meselson–Stahl (1958): ¹⁵N/¹⁴N labelling proved replication is semi-conservative; generation 1 is all hybrid, and the hybrid fraction halves every generation after that.
- Enzyme order: helicase unwinds → SSB proteins hold the strands apart → primase lays a primer → polymerase extends 5′→3′ → ligase seals the joins.
- Leading strand: continuous, one primer. Lagging strand: built in Okazaki fragments, many primers.
- Proofreading is polymerase's own job; mismatch repair catches the rest, bringing the final error rate below one in a billion bases.
- Real-world uses: PCR, DNA fingerprinting, forensic identification, whole-genome sequencing.
Frequently asked questions
What is DNA replication?
DNA replication is the process by which a DNA molecule makes two identical copies of itself, with each new copy carrying one original strand and one newly built strand.
Why is DNA replication called semi-conservative?
Because every newly formed double-stranded DNA molecule keeps (conserves) one strand from the original molecule and gains one brand-new strand. The Meselson-Stahl experiment (1958) proved this directly.
What did the Meselson-Stahl experiment prove?
Using heavy (¹⁵N) and light (¹⁴N) nitrogen-labelled DNA, they showed that after one generation all the DNA was hybrid, and after a second generation half was hybrid and half fully light — the exact pattern semi-conservative replication predicts.
What does helicase do?
Helicase breaks the hydrogen bonds holding the two original DNA strands together, separating them and creating the replication fork.
What is the difference between the leading and lagging strand?
The leading strand is made continuously in the same direction the replication fork moves, using just one primer. The lagging strand is made in short, separate Okazaki fragments running the opposite way, each needing its own primer, later joined by ligase.
What is an Okazaki fragment?
An Okazaki fragment is one of the short DNA pieces synthesised on the lagging strand during replication, first identified by Reiji and Tsuneko Okazaki in 1968. Ligase joins successive fragments into one continuous strand.
What does Chargaff's rule state?
In any DNA molecule, the amount of adenine equals the amount of thymine (%A = %T) and the amount of guanine equals the amount of cytosine (%G = %C), even though the overall A+T to G+C ratio varies between species.
How many hydrogen bonds hold an A-T pair and a G-C pair together?
An adenine-thymine pair is held by two hydrogen bonds; a guanine-cytosine pair is held by three, which is why GC-rich DNA is more heat-stable than AT-rich DNA.
Does DNA polymerase ever make mistakes?
It makes a small number, but its own 3′→5′ proofreading activity catches almost all of them; whatever slips through is largely caught afterward by mismatch repair, leaving a very low final error rate.
Where is DNA replication used in real life?
The same principle powers PCR (copying tiny DNA samples into billions of copies), DNA fingerprinting and forensic identification, whole-genome sequencing, and RT-PCR testing for diseases such as COVID-19.
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