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Electromagnetic induction: drag a magnet through a coil and watch

Electromagnetic induction is the production of an emf in a coil whenever the magnetic flux through it changes with time. Faraday's law states e = −N dΦ/dt, and the minus sign is Lenz's law: the induced current always flows in the direction that opposes the very change that created it.

Drag the magnet yourself, or just let it swing through the coil on its own.

North pole (N)South pole (S)CoilFlux vs time (Φ–t)Induced emf vs time (e–t)
Speed

Controls

200
1.0 ×
1.0 ×

Readings

Distance from coil centre, x
-16.0cm
Magnet's velocity, v
0.00m/s
Flux per turn, Φ
0.0μWb
Induced emf, e
0.0mV
Induced current, I
0.0mA
Coil's near-face pole
—
The magnet is
still

How to use this simulation

  1. Just let it go first: the magnet swings through the coil on its own and the galvanometer needle swings back and forth.
  2. Grab the magnet and drag it yourself: pull it fast and the needle swings further than when you pull it slowly — e grows with the magnet's speed v.
  3. Press "Flip the magnet": the needle now swings the opposite way, because the pole facing the coil has swapped.
  4. Raise the number of turns, N: the emf reading grows in direct proportion to N — the table below shows the same thing.
  5. Compare the two graphs on the right: wherever Φ is changing most steeply, e is largest at that exact instant — that is e = −N dΦ/dt, drawn out.

A bicycle dynamo, a wireless charger and a metal detector

Ride a bicycle at night and a small dynamo on the wheel spins a magnet next to a coil, and the headlamp lights up — no battery needed. That is exactly this simulation: a magnet moving near a coil changes the flux through it, and that change is what lights the lamp.

A phone charging wirelessly on a pad works on the same idea: two coils face each other, a rapidly changing current in one induces an emf in the other, with no wire between them. A metal detector finding a coin underground, an induction stove heating a pan directly, a guitar pickup turning a vibrating string into sound — all of it comes down to one fact: a changing magnetic flux creates an emf.

The two questions that matter are exactly how large that emf is, and which way the induced current flows. Those are Faraday's law and Lenz's law respectively. Grab the magnet in the simulation above and watch the galvanometer respond.

Starting from zero: magnetic flux and what "induced" means

How much magnetic field passes through a given area is called magnetic flux, symbol Φ. If the field B is perpendicular to the area A, then Φ = BA; if the field makes an angle θ with the perpendicular, Φ = BA cosθ. A coil of N turns links N times as much flux, called the flux linkage, NΦ.

Here is the key idea: flux by itself does nothing. A magnet sitting perfectly still inside a coil produces a large flux but no emf whatsoever. An emf appears only when the flux changes with time — the magnet moves, its strength changes, or the coil turns. This whole phenomenon, an emf appearing because flux is changing, is electromagnetic induction, and the emf it produces is the induced emf.

The English scientist Michael Faraday discovered this in 1831. He moved a magnet near a coil connected to a galvanometer and saw the needle move — but only while the magnet was actually moving. Hold it still and the needle stops. The American scientist Joseph Henry observed essentially the same effect independently around the same time. This one observation is the seed of every generator, transformer and power station running today.

In the simulation, hold the magnet perfectly still (stop dragging it and pause the auto-swing): the needle sits dead centre at zero. It responds only once the magnet starts moving again.

Key terms in electromagnetic induction

Get the vocabulary straight first; definition questions in exams come straight from this table.

TermSymbolWhat it meansSI unit
Magnetic fluxΦThe amount of magnetic field passing through an area, Φ = BA cosθweber (Wb)
Magnetic flux densityBField strength per unit areatesla (T)
Flux linkageNΦTotal flux "seen" by an N-turn coil, N times the flux per turnweber-turns
Induced emfeThe emf that appears because flux is changingvolt (V)
Induced currentIThe current that flows in a closed circuit because of the induced emfampere (A)
Number of turnsNHow many times the wire is wound around the coil—
Galvanometer—An instrument for tiny currents; a centre-zero one also shows direction—
Eddy current—A swirling current induced inside a solid conductor by a changing fluxampere (A)

Faraday's law: e = −N dΦ/dt

Faraday's law of electromagnetic induction states that the emf induced in a coil is proportional to the rate of change of flux linkage, and opposite in sign to it: e = −N dΦ/dt. Here dΦ/dt is how quickly the flux per turn is changing, and multiplying by N scales it up to the whole coil's induced emf.

Three consequences follow directly. First, a faster-changing flux (pulling the magnet quickly, or spinning it faster) gives a larger e. Second, more turns N means the same rate of flux change produces proportionally more total e — try changing the turns slider in the simulation to see this directly. Third, the flux itself does not need to be large, only changing: a weak magnet moved quickly can beat a strong magnet held still, which gives exactly zero emf.

In exam problems dΦ/dt is often written as the average rate ΔΦ/Δt, when the flux changes at a steady pace. Most of the worked problems below use this average form, since school-level problems almost always assume a steady rate of change.

e = −N dΦ/dtthe instantaneous induced emf

e = −N ΔΦ/Δtwhen flux changes at a steady rate

Lenz's law: what the minus sign actually says

The minus sign in Faraday's law is not decoration; it is Lenz's law: the induced current always flows in whichever direction opposes the very change in flux that produced it. As the magnet approaches, flux is increasing, so the induced current creates a magnetic field that opposes that increase — the coil's near face develops the same pole as the magnet's leading pole, so like poles repel and the coil resists the approach.

As the magnet moves away, the opposite happens: flux is decreasing, so the induced current now creates a pole opposite to the magnet's trailing pole, so opposite poles attract and the coil tries to pull the magnet back. That is exactly why the simulation shows one pole label as the magnet comes in and the opposite one as it leaves — the coil is always fighting whatever the magnet is doing.

Lenz's law is really a statement of energy conservation. If it worked the other way round — the induced current helping the magnet along instead of opposing it — the magnet would accelerate on its own, generating energy from nothing, which never happens. That is why you have to push the magnet to move it against the coil's opposition, and the work you do against that opposition is exactly the electrical energy you get out.

Try these experiments in the simulation

Predict what will happen before each experiment, then check.

  • Drag the magnet very slowly across, then drag the same path very fast. How much further does the needle swing when you go fast?
  • Press "Flip the magnet" and repeat the same drag speed. Which way does the needle swing now, compared with before?
  • Double the number of turns, N, keeping everything else the same. Does the emf reading really double?
  • Turn magnet strength all the way down, then all the way up. How does the height of the peak on the Φ–t graph change?
  • Hold the magnet perfectly still right at the coil's centre. Φ is still large there — so why does e read zero?
  • Set the oscillation speed to its slowest. Does the e–t graph look flatter or steeper than before?

Solved problems

Every solution states what is given, then the formula, then the substitution — write it this way in exams to get full marks.

Problem 1: peak flux in the simulation's own coil

The simulation's coil has radius 2 cm, so its area is A = πr² ≈ 12.57 cm². With the magnet centred and strength at 1×, the field there is B = 0.05 T. What is the flux per turn?

Φ = BA = 0.05 × (12.57 × 10⁻⁴ m²) ≈ 62.83 μWb. That is exactly the peak reading shown on the flux readout when you drag the magnet to the coil's centre.

Problem 2: a field changing at a steady rate

A coil of 150 turns, area 0.02 m², sits in a magnetic field that rises steadily from 0.20 T to 0.50 T in 0.50 s. What is the average induced emf?

ΔΦ = ΔB × A = (0.50 − 0.20) × 0.02 = 6.0 mWb. e = N ΔΦ/Δt = 150 × 6.0 mWb / 0.50 s = 1.80 V.

Problem 3: a moving rod (motional emf)

A straight conducting rod 0.50 m long moves at 4.0 m/s, perpendicular to a uniform field of 0.30 T. What emf appears across its ends?

The motional-emf formula is e = BLv. Substituting, e = 0.30 × 0.50 × 4.0 = 0.60 V. This is the same induction, seen from a rod's point of view rather than a coil's.

e = BLvwhen B, L and v are mutually perpendicular

Problem 4: a single loop with linearly changing flux

A single-turn loop's flux rises from 2.0 mWb to 8.0 mWb over 0.20 s. What is the induced emf?

With N = 1, e = ΔΦ/Δt = (8.0 − 2.0) mWb / 0.20 s = 6.0 mWb/s = 30.0 mV. An emf this small is easy to see on a sensitive galvanometer, but lighting a bulb needs far more turns — which is why real generators wind hundreds of turns.

Problem 5: Lenz's law together with Ohm's law

A coil of resistance 2 Ω briefly has an emf of 6 V induced in it, because a magnet is approaching. What current flows, and which way?

I = e/R = 6 / 2 = 3.0 A. By Lenz's law this current flows so as to make the coil's near face match the magnet's approaching pole, opposing the approach.

Problem 6: peak emf of an AC generator

An AC generator has a coil of 500 turns, area 0.05 m², rotating in a field of 0.40 T at 50 Hz — the same frequency as mains electricity. What is its peak emf?

The angular frequency ω = 2πf = 2π × 50 ≈ 314.16 rad/s. For a rotating coil, e₀ = NBAω = 500 × 0.40 × 0.05 × 314.16 ≈ 3,141.6 V, about 3.14 kV. A generator producing this much voltage is stepped down through transformers before it ever reaches a home.

e₀ = NBAωω = 2πf, for a coil rotating in a uniform field

Problem 7: power lost in the coil's own resistance

A coil has an induced emf of 12 V and a resistance of 6 Ω. How much power is dissipated as heat inside it?

P = e²/R = 12² / 6 = 24.0 W. This is exactly the heat that eddy currents waste inside a transformer core, which is why cores are built from thin laminated sheets to keep those currents small.

Problem 8: total charge through a coil

A coil of 300 turns has a flux per turn that changes by 4.0 mWb, and the coil's total resistance is 5 Ω. How much charge flows through it during that change?

q = NΔΦ/R = 300 × 4.0 mWb / 5 = 0.24 C. Notice time never enters this formula — the charge depends only on the total change in flux, not on how quickly it happened.

How the induced emf scales with the number of turns

Holding the rate of flux change fixed (here 5.0 mWb/s), e grows in direct proportion to N, because N multiplies the rate directly in the formula. Try the turns slider in the simulation to check this proportionality yourself.

Turns, NRate of flux changeInduced emf, e
1005.0 mWb/s0.50 V
2005.0 mWb/s1.00 V
3005.0 mWb/s1.50 V
4005.0 mWb/s2.00 V

Common mistakes

Avoiding these keeps marks safe on both the numeric and the conceptual questions.

  • Thinking a large flux by itself gives a large emf. What matters is the rate of change; a huge but unchanging flux gives e = 0.
  • Dropping the minus sign, or treating it as decoration. That sign is Lenz's law — it tells you the direction of the induced current.
  • Confusing flux Φ (per turn) with flux linkage NΦ (the whole coil). A coil's total induced effect scales with N, not just Φ.
  • Applying e = BLv without checking the condition. It only holds when the field, the rod's length and its velocity are all mutually perpendicular.
  • Treating motional emf (e = BLv) and Faraday's general law (e = −N dΦ/dt) as two unrelated formulas. They describe the same physics from two different bookkeeping angles.
  • Assuming eddy currents are always a nuisance. They waste energy in a transformer core, but the very same eddy currents are exactly what makes an induction stove or an eddy-current brake work.
  • Assuming the needle keeps deflecting the same way forever. The moment the magnet passes through and starts receding, the deflection reverses.

Real-life uses of electromagnetic induction

This single principle sits underneath most of the modern electrical world, well beyond the exam.

  • Power-station generators: a turbine spins a coil or magnet, changing flux and producing enormous induced emfs.
  • Transformers: a changing flux in one coil induces an emf in a neighbouring coil, stepping voltage up or down by the ratio of turns.
  • Wireless charging: a changing magnetic field between two coils carries energy across with no wire at all.
  • Induction cooktops: a rapidly changing field induces eddy currents directly in the base of the pan, heating the metal itself.
  • Metal detectors and contactless cards: a changing field induces a current in nearby metal or in a chip, which sends back a signal.
  • Regenerative braking in electric cars: the motor is run as a generator while slowing down, turning kinetic energy back into stored charge.
  • Guitar pickups and some microphones: a vibrating string or diaphragm changes the flux through a nearby coil, turning motion into an electrical signal.

Exam corner

Electromagnetic induction is a staple topic across school and college physics: expect a statement-and-derive question on Faraday's and Lenz's laws, a conceptual question on why the minus sign matters, and a numeric question using e = −N dΦ/dt or e = BLv.

A typical exam-style question

Setup: A student moves a bar magnet quickly toward a coil of 150 turns, then pulls it back at the same speed. The galvanometer needle deflects one way, then the other.

Questions typically asked: (a) Define magnetic flux. (b) State Lenz's law. (c) Explain why the needle would not move if the magnet were held still. (d) Explain, using Faraday's and Lenz's laws, why the needle deflected in opposite directions.

For (c): with dΦ/dt = 0, e = −N dΦ/dt gives e = 0 directly. For (d): flux increases while approaching and decreases while receding, so dΦ/dt changes sign, and by Lenz's law the induced current's direction reverses with it — seen as the needle swinging one way, then the other.

Revision: the one-screen summary

This list and the table above are all you need the night before an exam.

  • Electromagnetic induction: an emf appears whenever flux through a coil changes. Flux alone is not enough — it must change.
  • Faraday's law: e = −N dΦ/dt, or e = −N ΔΦ/Δt for a steady rate of change.
  • Lenz's law: the induced current always opposes its own cause — repelling an approaching magnet, attracting a receding one.
  • Motional emf: e = BLv, when B, L and v are mutually perpendicular.
  • Peak emf of a rotating coil: e₀ = NBAω.
  • e is proportional to both N and dΦ/dt; flux linkage = NΦ.
  • Eddy currents: induced swirling currents inside a solid conductor — wasteful in a transformer core, useful in an induction stove.

Frequently asked questions

What is electromagnetic induction?

Electromagnetic induction is the appearance of an emf in a coil whenever the magnetic flux through it changes with time. Michael Faraday discovered it in 1831.

What does Faraday's law state?

The induced emf is proportional to the rate of change of flux linkage, with a minus sign: e = −N dΦ/dt, where N is the number of turns and Φ is the flux per turn.

What is Lenz's law, and what does the minus sign mean?

Lenz's law says the induced current always flows in the direction that opposes the very change in flux that produced it. The minus sign in Faraday's law is exactly this statement of direction.

Does a stationary magnet inside a coil produce an emf?

No. The flux may be large, but it is not changing, so dΦ/dt = 0 and e = −N × 0 = 0. Hold the magnet still in the simulation and the galvanometer needle stays at zero.

What happens to the induced emf if you increase the number of turns?

At a fixed rate of flux change, e grows in direct proportion to N, because N multiplies the rate directly. For example, at one fixed rate, a coil of 200 turns gives exactly twice the emf of a coil with half as many turns.

When does the motional emf formula e = BLv apply?

When a straight conducting rod moves through a uniform magnetic field such that the field, the rod and its velocity are all mutually perpendicular. It is a special case of Faraday's general law.

What is an eddy current, and is it always bad?

An eddy current is a swirling current induced inside a solid conductor by a changing flux. It wastes energy as heat inside a transformer core, but the very same effect is put to good use in induction cooktops and eddy-current brakes.

How can a generator produce a larger peak emf?

From e₀ = NBAω, increasing the number of turns N, the field strength B, the coil area A, or the angular speed ω all increase the peak emf.

Why does the galvanometer needle swing further when you drag the magnet faster?

Dragging faster changes the flux over the same distance in less time, so dΦ/dt is larger, and by e = −N dΦ/dt the induced emf and current are larger too, deflecting the needle further.

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The animation made the idea click; now turn it into marks. Syllabus, suggestions, textbooks and admission-test guides are below.

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