Controls
Readings
- Sarcomere length
- 2.50µm
- A band
- 1.60µm
- I band
- 0.90µm
- H zone
- 0.50µm
- Shortening vs rest
- 0.0%
- Relative force
- 79%
- Strokes per head needed
- 0
- Current step
- Rest: no calcium, heads free
How to use this simulation
- Leave the sarcomere at its resting length and read the three bands in the chart at the bottom: the A band is 1.60 µm, the I band is 0.90 µm and the H zone is 0.50 µm. Show labels is on, so every part of the diagram is named.
- Press Contract. Calcium switches on, the purple strand beside every thin filament slides aside, the myosin heads in the overlap zone start to cycle and the two Z lines glide toward each other.
- Keep your eye on the bars. The sarcomere bar, the I band bar and the H zone bar shrink, but the A band bar never moves. That single observation is the sliding-filament theory.
- Switch Calcium ions present off in the middle of a contraction. The strand slips back over the binding sites, the heads let go and the muscle stops pulling. The step reading says Rest.
- Switch ATP present off while calcium is on. The heads latch onto actin and stay there: this is rigor, the same state as rigor mortis. Switch ATP back on and the cycle resumes.
- Drag the sarcomere length slider to the far right. As the thin filaments pull out of the thick ones, the relative force reading falls toward zero. Drag it left past 2.0 µm and the force falls again as the filaments crowd.
The bag of rice problem
You lift a bag of rice from the floor to the kitchen shelf. Your biceps bulges, your elbow bends, the bag rises. The muscle got shorter and fatter, and it did it in about a second. The question that puzzled biologists for a long time was how.
The obvious guess is that the muscle is made of long molecular ropes that scrunch up like a spring when you tell them to. That guess is wrong, and the experiment that overturned it is lovely. Under a microscope the bands of a contracting muscle do not all get shorter. One dark band stays exactly the same width. The light bands on either side of it narrow, and the pale stripe in the middle of the dark one closes up.
In 1954 two teams, Hugh Huxley with Jean Hanson, and Andrew Huxley with Rolf Niedergerke, explained this at once. The muscle is built of two interleaved sets of filaments, and contraction is those sets sliding past each other like two combs being pushed together. Nothing in either set shrinks.
This page lets you run that machine. You will squeeze a sarcomere, watch the bands change, break the system by taking away calcium or ATP, and calculate how many tiny pulls a single myosin head needs to shorten a muscle.
From muscle to sarcomere: the zoom ladder
A skeletal muscle looks like one piece of meat, but it is a bundle of bundles. Zoom in step by step and the structure becomes clear.
- A whole muscle (the biceps) is wrapped in connective tissue and made of bundles called fascicles.
- Each fascicle holds many muscle fibres, which are single giant cells with many nuclei, up to several centimetres long.
- Each fibre is packed with rod-shaped myofibrils running along its length, a few micrometres thick.
- Each myofibril is a chain of identical units called sarcomeres, joined end to end. This is the unit that does the shortening.
- Each sarcomere holds two kinds of protein filament: thin filaments of actin, about 1.0 µm long, and thick filaments of myosin, 1.6 µm long.
Words you need first
Most of the marks in this chapter are definitions and labelled diagrams. Learn each term with the one next to it, because examiners like to ask for pairs.
| Term | What it means |
|---|---|
| Sarcomere | The contractile unit of a muscle: the stretch between two neighbouring Z lines. |
| Myofibril | A long thread inside a muscle fibre made of sarcomeres in a row. |
| Actin | The protein of the thin filaments. It carries the binding sites for myosin heads. |
| Myosin | The protein of the thick filaments. Each molecule has a tail and a pair of swivelling heads. |
| Z line (Z disc) | The dark boundary of a sarcomere to which the thin filaments are anchored. |
| M line | The line in the middle of the sarcomere that holds the thick filaments in place. |
| Tropomyosin | A thread winding along actin that covers the myosin binding sites at rest. |
| Troponin | A small protein complex on tropomyosin that binds calcium and moves the thread aside. |
| Cross-bridge | A myosin head attached to a binding site on actin. |
| Sarcoplasmic reticulum | The muscle cell’s calcium store, wrapped around every myofibril. |
| Neuromuscular junction | The synapse where a motor neuron talks to a muscle fibre using acetylcholine. |
Reading the bands of a sarcomere
Under a microscope a sarcomere shows alternating dark and light bands. Each band is simply a region where the filaments overlap or do not. This is the part of the chapter that decides whether the sliding-filament theory makes sense to you, so go slowly.
The A band (dark) is as long as the thick filaments, 1.6 µm. It contains the thick filaments and any thin filaments that have slid into them. The I band (light) holds only thin filaments, so it is the part of the sarcomere that is not the A band. The H zone is the pale patch in the middle of the A band where there are thick filaments only, and the M line runs through it.
I band = sarcomere − A bandboth in µm; the I band is what is left of the sarcomere
H zone = sarcomere − 2 × thin filamentzero once the thin filaments meet in the middle
| Band | Contains | Resting size | During contraction |
|---|---|---|---|
| A band | Thick filaments (plus overlapping thin ones) | 1.6 µm | Stays the same |
| I band | Thin filaments only | 0.9 µm | Gets shorter |
| H zone | Thick filaments only | 0.5 µm | Gets shorter, may vanish |
| Sarcomere | Everything between two Z lines | 2.5 µm | Gets shorter |
The sliding-filament model in plain words
Picture two combs facing each other with their teeth interleaved. Push the combs together and the whole thing gets shorter, but no tooth got shorter. The combs are the Z lines with their thin filaments, and the teeth between them are the thick filaments.
In a sarcomere the thin filaments hang from the two Z lines and the thick filaments float in the middle, held by the M line. Myosin heads stick out of each thick filament toward the thin ones. When the heads grab actin and bend, they drag the thin filaments toward the M line. The Z lines come closer, so the sarcomere shortens from 2.5 µm toward 2.0 µm.
Notice what shrinks. The I band shrinks because the thin filaments slide into the A band. The H zone shrinks because the tips of the thin filaments move toward each other. Neither the thick nor the thin filaments change length at all.
Now multiply. A myofibril has thousands of sarcomeres in a row, and the fibre has hundreds of myofibrils side by side. When every sarcomere shortens by a little, the whole muscle shortens by a lot.
The cross-bridge cycle, step by step
One myosin head moves the thin filament only a few nanometres each time it works. Muscle gets its power from thousands of heads doing this together, each one repeating the same four-step cycle. The simulation shows the cycle on its heads in the overlap zone; watch the Current step reading as the heads move.
Step 1: attachment
The head, already charged with the products of ATP splitting (ADP and phosphate), is cocked like a pulled-back arm. Once calcium has uncovered the binding site on actin, the head latches onto it. The attached head is called a cross-bridge.
Step 2: the power stroke
The head releases ADP and phosphate and swivels toward the M line, dragging the thin filament about 10 nm with it. This is the step that does the work, and the one that makes the sarcomere shorter. At the end of the stroke the head is bent forward and still attached.
Step 3: detachment
A fresh ATP molecule binds to the head. This is the reason ATP is needed to relax the muscle as well as to contract it: only a head that has bound new ATP can let go of actin.
Step 4: re-cocking
The head splits that ATP into ADP and phosphate. The energy released snaps the head back to its cocked position, ready to attach again if the binding site is still open, farther along the thin filament. If calcium has gone, the head stays detached and the muscle relaxes.
Calcium and ATP: the two switches
A resting muscle is not slack by accident. Two things must be present before the cycle can run, and the simulation lets you remove either one.
First, calcium. At rest the strand of tropomyosin lies across the binding sites on actin, so the heads have nothing to grab. A nerve impulse reaches the muscle fibre through the neuromuscular junction, the fibre’s membrane fires, and the sarcoplasmic reticulum releases calcium ions into the cell. Calcium binds to troponin, troponin shifts tropomyosin aside, and the sites are open. Pump the calcium back and the sites are covered again.
Second, ATP. ATP does two jobs: its splitting cocks the head, and its fresh binding releases the head from actin. Without ATP the heads attach and cannot detach, so the muscle goes stiff. That is rigor, and it is why a dead body stiffens: ATP production stops, the pumps stop, calcium leaks out of the reticulum, and the heads freeze onto actin until the proteins start to break down.
- Nerve impulse arrives at the neuromuscular junction (acetylcholine released).
- The impulse spreads along the fibre membrane and into the cell.
- Calcium is released from the sarcoplasmic reticulum.
- Calcium binds troponin, tropomyosin moves aside, binding sites open.
- Cross-bridge cycle runs for as long as calcium and ATP are present.
- Calcium is pumped back, sites close, the muscle relaxes.
How long is the sarcomere, and how hard can it pull?
Force depends on how many heads can reach actin, and that depends on the overlap between the filaments. If the sarcomere is stretched until thin and thick filaments barely touch, there are almost no cross-bridges and almost no force. At about 2.0 to 2.2 µm the overlap is full and the force is at its peak. If the sarcomere is squeezed much shorter, the thin filaments crowd past each other in the middle and the thick filaments hit the Z lines, so the force falls again.
In the simulation the relative force at the resting length of 2.5 µm is 79 % of the maximum. You can check this with the relative-force reading: at 2.1 µm it reads 100 %, at 3.0 µm it reads 45 %, and by 3.2 µm only 31 % is left. The curve is idealised, but the shape is the real one.
Try it in the simulation
Spend ten minutes on these. Each one is a question an examiner could ask, answered by what you see on the diagram.
- Press Contract on the defaults. Which two bands shrink and which one does not move?
- Pause during the contraction and name the step of the cross-bridge cycle shown in the Current step reading. Resume and watch it change.
- While contracting, switch Calcium ions present off. What do the heads do and what happens to the sarcomere?
- Switch ATP present off with calcium on. What does the step reading say, and why does the muscle not relax?
- Drag the sarcomere length to 2.0 µm. What is the H zone now?
- Drag it to 3.4 µm. How does the relative force compare with the value at 2.1 µm?
- Hide the labels and name the Z line, M line, A band, I band and H zone from memory, then show them to check.
Solved problems
Each solution states the rule first, then substitutes the numbers, the order you should write it in an exam. Every figure is computed by the same code that drives the simulation.
Problem 1: the bands of a resting sarcomere (2.5 µm)
The A band is the thick filament length, 1.6 µm. I band = sarcomere − A band = 2.5 − 1.6 = 0.9 µm. H zone = sarcomere − 2 × thin filament = 2.5 − 2 × 1.0 = 0.5 µm. Those are the numbers on the bars when the page loads.
Problem 2: a firm contraction to 2.0 µm
I band = 2.0 − 1.6 = 0.4 µm. H zone = 2.0 − 2 × 1.0 = 0.0 µm, so the H zone has vanished. The A band is still 1.6 µm. The sarcomere has shortened by (2.5 − 2.0) ÷ 2.5 × 100 = 20 %.
Problem 3: how far does each thin filament slide?
Each sarcomere has two Z lines, and each Z line moves inward by half of the total shortening. Slide per thin filament = (2.5 − 2.0) ÷ 2 = 0.25 µm = 250 nm. One power stroke moves it 10 nm, so one head would need 250 ÷ 10 = 25 strokes. In practice hundreds of heads share the work, and each cycles many times.
Problem 4: contracting as far as 1.8 µm
Slide per thin filament = (2.5 − 1.8) ÷ 2 × 1000 = 350 nm, which is 35 strokes of 10 nm. The I band is 1.8 − 1.6 = 0.2 µm. The sarcomere is 28 % shorter than at rest, and the relative force has dropped to 83 % because the thin filaments now overlap each other in the middle.
Problem 5: a stretched sarcomere (3.2 µm)
I band = 3.2 − 1.6 = 1.6 µm and H zone = 3.2 − 2 = 1.2 µm, both much larger than at rest. Each thin filament now overlaps each half of the A band by only 0.2 µm, so few heads can reach actin. The idealised force is 31 % of the maximum.
Problem 6: a whole 30 cm muscle
One centimetre of fibre holds 10,000 ÷ 2.5 = 4,000 sarcomeres at rest, so 30 cm holds 120,000. If every one of them shortens from 2.5 µm to 2.0 µm, the muscle gets shorter by 30 × 10 × (1 − 2.0 ÷ 2.5) = 60 mm, which is 6 cm. A tiny change in each sarcomere adds up to a visible movement.
Problem 7: the ATP bill
Suppose one thick filament carries 300 heads and each cycles 5 times a second, using one ATP per cycle. ATP use = 300 × 5 = 1,500 molecules per second for that single filament. A muscle fibre has millions of thick filaments, which is why a hard-working muscle needs a huge supply of ATP and gets hot. These numbers are illustrative; the idea is the point.
Problem 8: comparing 2.1 µm and 3.0 µm
At 2.1 µm the sarcomere sits on the plateau of the length-tension curve, so the relative force is 100 %. At 3.0 µm only part of the thick filament is overlapped by actin and the force is 45 %. The sarcomere pulling at 3.0 µm is therefore weaker, even though it is being stretched harder.
Common mistakes
These are the slips that cost marks every year.
- Saying the filaments shorten. They do not; they slide. The A band is the proof.
- Saying the A band shortens. The I band and H zone shorten, the A band does not.
- Writing that ATP is needed only to make the muscle contract. ATP is also needed for the head to let go and for the calcium pump.
- Forgetting that calcium acts on troponin, and troponin moves tropomyosin. Calcium does not bind actin directly.
- Confusing the Z line with the M line. Z lines are the sarcomere’s ends; the M line is in the middle.
- Drawing the thin filaments attached to the M line. They hang from the Z lines.
Where you see it in real life
Rigor mortis begins a few hours after death and fades after a day or two. The reason is exactly what you simulated: no ATP, so the heads cannot detach. When the muscle proteins later break down, the body relaxes again. Forensic scientists use the stiffening to estimate the time of death.
A cramp is a sustained involuntary contraction. Often it comes from tired, ion-imbalanced muscle that keeps firing, so the heads keep cycling when you want them to stop. Stretching helps because it pulls the thin filaments back out and breaks the overlap.
Heart muscle uses the same sliding filaments. Cardiac fibres are striated too, and they also depend on a rapid pulse of calcium for each beat, which is why calcium-channel blockers are a common heart medicine.
Exam corner
Typical questions, and what a full-mark answer contains.
| Question | Key points |
|---|---|
| Define a sarcomere | The functional unit of a myofibril between two adjacent Z lines. |
| Describe the sliding-filament theory | Actin filaments slide over myosin toward the M line; cross-bridges attach, pivot, detach; the filaments keep their length; the sarcomere shortens. |
| What changes and what stays the same? | I band and H zone shorten, the A band stays the same. |
| Role of calcium | Released from the sarcoplasmic reticulum, binds troponin, moves tropomyosin and exposes the binding sites. |
| Role of ATP | Cocks the head and releases the head from actin; powers the calcium pump. |
| Explain rigor mortis | No ATP, so the heads cannot detach from actin and the muscle stays stiff. |
Revision summary
A sarcomere runs from Z line to Z line and shortens from about 2.5 µm during contraction. Thin actin filaments hang from the Z lines; thick myosin filaments (1.6 µm) sit in the middle. Calcium, released from the sarcoplasmic reticulum, binds troponin and moves tropomyosin so that myosin heads can attach. Each head attaches, makes a power stroke of about 10 nm, detaches when new ATP binds, and re-cocks by splitting it. The A band stays constant; the I band and H zone shorten. With no calcium the muscle relaxes, with no ATP it locks in rigor, and the force is greatest around 2.0 to 2.2 µm.
Frequently asked questions
What is the sliding-filament theory?
It says that a muscle shortens because thin actin filaments slide past thick myosin filaments toward the centre of each sarcomere, pulled by myosin cross-bridges. The filaments themselves do not change length.
Which band does not change length when a muscle contracts?
The A band, which is as long as the thick myosin filaments (1.6 µm in this model). The I band and H zone get shorter.
Why is ATP needed for muscle relaxation?
A myosin head can only let go of actin after a fresh ATP molecule binds to it. Without ATP the heads stay attached, as in rigor mortis, and the muscle cannot relax.
What does calcium do in muscle contraction?
Calcium ions from the sarcoplasmic reticulum bind troponin, which moves tropomyosin away from the myosin binding sites on actin so that cross-bridges can form.
What is the difference between the Z line and the M line?
Z lines mark the two ends of a sarcomere and anchor the thin filaments. The M line is in the middle and holds the thick filaments.
How far does a myosin head move the thin filament in one stroke?
Roughly 10 nm in this model, so many heads and many cycles are needed to shorten a sarcomere by hundreds of nanometres.
Keep studying this topic
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