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বাং

How to balance a seesaw with unequal weights

A lever is a rigid bar that can turn about a fixed point called the fulcrum. How strongly a force turns the bar is its moment, M = F × d, where d is the perpendicular distance from the fulcrum to the line of the force. When the anticlockwise and clockwise moments are equal, the bar stays balanced. Test it yourself in the simulation below.

Drag on the canvas to move the load or the effort

LoadEffortAnticlockwise momentClockwise momentFulcrum
Speed

Controls

Class of lever

60 N
2.0 m
40 N
3.0 m

Readings

Anticlockwise moment
120.0N·m
Clockwise moment
120.0N·m
Net moment
0.0N·m
Effort needed to balance
40.0N
Mechanical advantage, load ÷ effort
1.50
Arm ratio, d₂ ÷ d₁
1.50

How to use this simulation

  1. With “Class 1” selected, notice the defaults: 60 N at 2 m against 40 N at 3 m. The two moments match, so the beam sits level.
  2. Move the effort-arm slider, or drag the effort arrow on the canvas. Two coloured bars show the moments; the beam tips towards the bigger one.
  3. Change the effort force to restore balance, then compare your own calculation with the “Effort needed to balance” reading.
  4. Switch to class 2 and class 3. Watch which one gives a mechanical advantage above 1 and which one gives less than 1 in the readings panel.

A playground secret

You have probably ridden a seesaw. You are heavy, your friend is light. When you sit down, your end hits the ground and your friend dangles in the air. So what can you do so both of you hover level? One answer: slide towards the pivot while your friend stays at the far end. A light person can then lift a heavy one.

The same trick shows up everywhere: a crowbar shifting a boulder, a bottle opener, a wheelbarrow. Nobody says, “push harder.” They say, “hold it further out.” Distance is the real key.

In this lesson we give that key a name: the moment of a force. The rule is a single line, M = F × d, yet inside it hide seesaws, scissors, wheelbarrows, nutcrackers and even the way your own arm is built.

Start from zero: when does a push turn something?

Try opening a door by pushing near the hinge. Hard work! Push the handle, as far from the hinge as possible, and one finger does it. The force is the same, the result is not. Turning power depends on the force and also on how far from the pivot the force is applied.

The pivot, or fulcrum, is the point that does not move: the hinge of a door, the post in the middle of a seesaw. The further the line of the force sits from that point, the more it turns the object. And if the line of the force passes right through the pivot, it turns nothing at all. Push straight at the hinge and the door stays shut.

Physicists package this joint power of force and distance into one quantity, the moment of a force (often called torque). It measures the tendency to rotate, just as force measures the tendency to accelerate.

A turn has two possible senses: clockwise and anticlockwise. To add several moments you must give each sense its own sign. In the simulation we skip that bookkeeping by showing the two senses as two separate bars so they are easy to compare.

Words you must know

Exam questions on levers use the same few terms again and again. Keep each meaning next to a familiar example.

TermPlain meaningFamiliar example
LeverA rigid bar that turns about a fixed pointSeesaw, crowbar, Dhenki
FulcrumThe point the bar turns aboutThe seesaw’s centre post, a door hinge
LoadThe thing you want to lift or moveA boulder, sand in a wheelbarrow
EffortThe force you apply to handle the loadHand pressure on a crowbar
Load armPerpendicular distance from the fulcrum to the load’s line of forceThe short end of a crowbar
Effort armPerpendicular distance from the fulcrum to the effort’s line of forceThe long handle of a crowbar
Moment of a forceForce × perpendicular distance, unit N·mTightening a nut with a spanner
Mechanical advantageLoad ÷ effort, no unitAbove 1 means a small force moves a big load
Centre of gravityThe point where the whole weight can be taken to actThe middle of a uniform plank

Where the formula comes from: defining a moment

Pick a pivot O. A force F acts so that the perpendicular distance from O to its line of action is d. That d is the arm of the force. By definition, the moment of the force is the product of force and arm.

On a seesaw the beam is horizontal and the weights pull straight down, so the distance measured along the beam is the perpendicular distance. If the beam tilts, the line of force stays vertical but the perpendicular distance shrinks by a factor of cosθ. The tilt in the simulation is small, so the simple formula is enough here.

The unit drops straight out of the formula: newton times metre, N·m. It looks like the joule, yet the two are different things. A joule measures energy and work. A moment measures the tendency to turn, so write N·m.

M = F × dmoment = force × perpendicular distance from the pivot

[M] = N·munit check, newton times metre

M′ = F × d × cosθeffective arm when the beam is tilted by θ from the horizontal

The principle of moments: one condition for balance

When several forces act on a body, each one tries to turn it its own way, some clockwise, some anticlockwise. If the efforts cancel out to zero, the body does not turn. That is the principle of moments: for a body in rotational balance, the sum of the anticlockwise moments about any point equals the sum of the clockwise moments about that point.

In the simulation’s starting state, 60 N acts 2 m from the fulcrum on one side and 40 N acts 3 m away on the other. The first moment is 60 × 2 = 120 N·m, the second 40 × 3 = 120 N·m. They are equal, so the beam is level.

Notice that the principle does not mention the beam’s own weight. That is because we assume the bar is light enough to ignore. A uniform heavy bar has its weight acting at its centre of gravity, the exact middle, and you add that as one more force. A worked example below does exactly that.

One more thing. When the bar is balanced the fulcrum pushes up with a force equal to all the downward forces together. That force has zero arm, so it never enters the moment equation. This is why choosing the fulcrum as your turning point makes the sums simplest.

Σ M(anticlockwise) = Σ M(clockwise)the principle of moments

W × d₁ = F × d₂one lever, two forces: load × load arm = effort × effort arm

F = W × d₁ ÷ d₂the effort needed to balance

Mechanical advantage: more load for less effort

Rearranging the balance condition gives load ÷ effort = effort arm ÷ load arm. The left side is the mechanical advantage. It tells you how many times the lever multiplies your effort. The right side is pure geometry, the two arm lengths.

Say the load is 600 N and its arm is 0.5 m. The longer you make the effort arm, the smaller the effort. The table below is computed in code, so you can check every row in the simulation.

But nothing is free. The longer the effort arm, the further your hand has to travel. Energy conservation says: smaller force, bigger distance. In an ideal lever the work put in equals the work got out.

MA = load ÷ effortdefinition, no unit

MA = d₂ ÷ d₁for an ideal lever: effort arm ÷ load arm

Effort arm (m)Effort needed (N)Mechanical advantage
0.56001.0
1.03002.0
1.52003.0
2.01504.0
3.01006.0

Three classes of lever: who sits in the middle?

Every lever has three parts: fulcrum, load and effort. Which one sits between the other two decides the class. An easy memory aid: classes 1, 2, 3 have the fulcrum, the load and the effort in the middle, in that order.

Class 1: fulcrum in the middle

Load on one side, effort on the other, the fulcrum between. Pushing the effort down lifts the load up, so the direction of force flips. A seesaw is the classic. Slide the fulcrum and the advantage changes: closer to the load, like a crowbar, gives a big gain; farther gives a loss.

Class 2: load in the middle

The fulcrum is at one end, the load near the middle, the effort at the far end. The effort arm is always longer than the load arm, so the mechanical advantage is always above 1. In a wheelbarrow the wheel axle is the fulcrum, the sand is the load and your hands on the handles give the effort. Lifting the handles upward raises a heavy load easily.

Class 3: effort in the middle

The fulcrum is at one end, the effort near the middle and the load at the far end. Here the effort arm is the short one, so the mechanical advantage is always below 1: you push harder than the load weighs. Why build such a lever? Because what you lose in force you gain in speed and range. A small movement near the fulcrum swings the load through a big arc. Your arm muscles work exactly this way.

ClassIn the middleMechanical advantageExamples
FirstFulcrumAbove, equal to or below 1, depending on the armsSeesaw, scissors, crowbar, balance scale
SecondLoadAlways above 1Wheelbarrow, nutcracker, bottle opener
ThirdEffortAlways below 1Tweezers, fishing rod, your forearm

Try it in the simulation

Each experiment takes a minute, but doing it once yourself means you will not forget the rule. Start from the defaults.

  • Experiment 1: in class 1, double the load force. Which way does the beam tilt? Now double the effort arm to restore balance.
  • Experiment 2: keep the load arm short and stretch the effort arm, then read “Effort needed to balance”. Effort falls while mechanical advantage rises.
  • Experiment 3: drag the effort position along the canvas. At the instant the two bars match, the beam stops. Write down the distance in metres.
  • Experiment 4: choose class 2 and try to put the effort closer than the load. The simulation keeps half a metre of gap, because otherwise it would no longer be a class 2 lever.
  • Experiment 5: in class 3 note that the mechanical advantage is below 1. In your own words, explain why the effort force exceeds the load force at balance.
  • Experiment 6: switch off “Show the arm lengths” and estimate the distances from the tick marks on the beam. Switch it on again to check.

Check a seesaw by arithmetic

The table below lists four pairs with their moments computed. Put each pair into the simulation and see whether it agrees.

Left force (N)Left distance (m)Right force (N)Right distance (m)Left moment (N·m)Right moment (N·m)Result
602.0403.0120120Balanced
602.0402.012080Left side goes down
303.0403.090120Right side goes down
501.5253.07575Balanced

Solved problems

Every number is computed in code. Write each step in your notebook before reading the next line.

Problem 1: where should the second person sit?

On a light seesaw a 300 N person sits 1.5 m from the pivot. Where must a 450 N person sit on the other side to balance?

The first moment is 300 × 1.5 = 450 N·m. At balance the other side needs 450 N·m too, so d = 450 ÷ 450 = 1.00 m. The heavier person sits closer.

Problem 2: which way does it turn?

A 80 N force acts downward 2 m left of the pivot and a 50 N force acts downward 3.5 m to the right. Which way does the bar turn and what is the net moment?

Anticlockwise moment: 80 × 2 = 160 N·m. Clockwise moment: 50 × 3.5 = 175 N·m. Clockwise wins, so the bar turns clockwise with a net moment of 175 − 160 = 15 N·m. The smaller force won because it sat further out.

Problem 3: a crowbar (class 1)

A crowbar has the load 0.2 m from the fulcrum and your hand 1.2 m away. What effort lifts a 1,200 N load, and what is the mechanical advantage?

Effort = 1,200 × 0.2 ÷ 1.2 = 200 N. Mechanical advantage = 1,200 ÷ 200 = 6. Only one sixth of the load’s weight does the job.

Problem 4: a wheelbarrow (class 2)

A wheelbarrow carries 600 N of sand 0.6 m from the wheel axle. The handles are 1.5 m from the axle. What upward force on the handles lifts it?

Take moments about the axle: effort × 1.5 = 600 × 0.6. So the effort is 240 N and the mechanical advantage is 2.5. Above 1, as a class 2 lever should give.

Problem 5: the forearm (class 3)

The elbow is the fulcrum. A 5 kg ball sits in the hand 0.35 m from the elbow while the biceps attaches only 0.04 m from it. Take g = 9.8 m/s² and find the biceps force.

The ball’s weight is 5 × 9.8 = 49 N. Effort = 49 × 0.35 ÷ 0.04 = 429 N. The mechanical advantage is 0.114, far below 1. The muscle pulls 8.75 times the ball’s weight. The body gives up force to buy speed and range.

Problem 6: a plank with weight

A uniform plank 4 m long weighs 120 N and is pivoted 1.5 m from its left end. A 150 N load hangs on the left end. What weight on the right end keeps it level?

The plank’s centre of gravity is in the middle, 0.5 m right of the pivot. Anticlockwise moment: 150 × 1.5 = 225 N·m. The plank’s own clockwise moment: 120 × 0.5 = 60 N·m. The right end is 2.5 m from the pivot, so 225 = 60 + X × 2.5 gives X = 66 N.

Mistakes that cost marks

The same few errors turn up in answer scripts year after year. Read the list and spot your own.

  • The distance is the perpendicular distance from the pivot to the line of the force, not just the straight-line distance to where it is applied. A slanted force shows the difference.
  • The unit of a moment is N·m, not J. They look alike but mean different things.
  • Measure every distance from the same pivot. Mixing two pivots in one problem is the most common slip.
  • Mixing up class 2 and class 3. Find who sits in the middle: the load or the effort.
  • Thinking a mechanical advantage below 1 means a bad lever. In class 3 it is normal, and you gain speed in return.
  • Forgetting the weight of a uniform bar. Put it at the centre of gravity and include its moment.
  • Adding moments without checking the sense. Clockwise and anticlockwise need opposite signs.

Levers hiding in daily life

Once you can spot them, levers are everywhere. A few samples:

  • Scissors: two class 1 levers joined, with the screw as the fulcrum.
  • Balance scale: a class 1 lever with equal arms, level when the two pan moments match.
  • Bottle opener: the rim is the fulcrum, the cap is the load and your hand is the effort, class 2.
  • Tweezers: class 3, ideal for gripping delicate things gently.
  • Fishing rod: class 3, a small movement of the hand swings the tip a long way.
  • Dhenki: an old village class 1 lever for husking rice, press with the foot and the other end rises.
  • Your body: nodding the head is class 1, rising on tiptoe is class 2, bending the arm is class 3.

Exam corner: CBSE and NCERT style

Board papers ask for definitions, short derivations and numericals. Here is a typical set.

Typical questions

1 mark: Define the moment of a force and state its SI unit.

2 marks: State the principle of moments and name one device that uses it.

3 marks: A 300 N weight is 1.5 m from the fulcrum. At what distance must a 450 N weight be placed on the other side to balance? Answer: 450 ÷ 450 = 1.00 m.

5 marks: Classify levers into three classes with a labelled diagram and one example each. Compare their mechanical advantage.

How to score full marks

Start every numerical with the equation, substitute the numbers with units and finish with a boxed answer. Examiners award a mark for the equation even if the arithmetic slips.

For classification questions, draw the three levers side by side with F, L and E marked. A neat diagram is worth half the answer.

Quick revision

Skim these few lines the night before the exam.

  • Moment M = F × d, in N·m, measures the tendency to rotate.
  • In balance the sum of anticlockwise moments equals the sum of clockwise moments.
  • For a lever, W × d₁ = F × d₂ and mechanical advantage = load ÷ effort = d₂ ÷ d₁.
  • Class 1 has the fulcrum in the middle, class 2 the load, class 3 the effort.
  • Class 2 always has an advantage above 1, class 3 always below 1, class 1 can be anything.
  • More advantage means more distance moved by the effort. Energy is not saved.
  • The weight of a uniform bar acts at its centre of gravity.

Frequently asked questions

Are the moment of a force and torque the same thing?

At school level, yes: both are force times the perpendicular distance from the pivot, measured in N·m. Some books say moment, others torque. In advanced courses torque is a vector pointing along the rotation axis, but this lesson only needs its size and its sense of turning.

Why is a lever with advantage below 1 still a lever?

Because the definition of a lever never promised a gain in force. Any rigid bar that turns about a fulcrum and transmits force is a lever. Class 3 loses force but gains speed and range of motion.

Can a seesaw balance if the fulcrum is not in the middle?

Yes. Wherever the fulcrum is, balance only needs equal moments on both sides. The distances will simply differ, and if the bar has weight of its own you must include its moment too.

How big is the force on the fulcrum at balance?

The fulcrum pushes up with a force equal to the total downward force on the bar. On a class 1 lever that is the two weights added together. That is why the support must be strong when you lift something heavy.

Why is the unit of a moment not the joule?

A joule measures energy or work, where the force acts along the displacement. In a moment the force and distance are perpendicular, and the quantity measures a tendency to turn, not an energy transfer. So the unit is written N·m.

Does a lever save energy?

No. In an ideal lever the work done by the effort equals the work done on the load. A smaller force means your hand moves a longer distance. A lever multiplies force or changes its direction, but the total energy stays the same.

Keep studying this topic

The animation made the idea click; now turn it into marks. Syllabus, suggestions, textbooks and admission-test guides are below.

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Mathematics

Pythagorean Theorem

Mathematics

Trigonometric Ratios and the Unit Circle

Mathematics

Quadratic functions and their graphs

Mathematics

Circle theorems

Mathematics

Heights and distances: elevation and depression angles

Mathematics

Probability: experimental vs theoretical probability

Mathematics

Arithmetic and Geometric Sequences

Mathematics

Mean, Median and Mode

Mathematics

Sets and Venn Diagrams

Mathematics

Linear equations: graphs, slope and simultaneous pairs

Mathematics

Graphs of sin, cos and tan

Mathematics

Completing the Square and the Quadratic Formula

Mathematics

Area of a Circle: Proof, Formula and Solved Problems

Mathematics

Volume and Surface Area of Solids: Cube, Cuboid, Cylinder, Cone, Sphere

Mathematics

Similar Triangles: Scale Factor, AA, SSS, SAS and Shadow Heights

Mathematics

Coordinate Geometry: Distance, Midpoint, Slope, Section Formula and Locus

Mathematics

Conic Sections: Circle, Ellipse, Parabola and Hyperbola

Mathematics

Function Transformations: Shifts, Stretches and Reflections

Mathematics

Derivative as the Slope of a Tangent: Secant to Tangent

Mathematics

Riemann Sums and Integration: Area Under a Curve

Mathematics

Limits and the ε–δ Definition: A Visual Guide

Mathematics

3D Vectors: Sum, Dot Product and Cross Product

Mathematics

Matrix Transformations: Rotation, Reflection, Shear and the Determinant

Mathematics

Complex Numbers: Sum, Product, Powers and Roots on the Argand Plane

Mathematics

Binary Number System: Place Value, Conversion and Addition